Question

find the probability of receiving a prime number in the experiment of throwing a balanced diet once​

Answer 1

Answer:

1/2

Step-by-step explanation:

Total no. in dice is 6

P(E) = no of favorable outcomes/total no of outcomes

=3/6

= 1/2

Answer 2

$P(E)=\dfrac{1}{2}$

Step-by-step explanation:

When a dice thrown once​,

All possible outcomes are:

1, 2, 3, 4, 5, 6

Total number of possible outcomes = 6

Let E be the event of getting a prime number.

All favourable outcomes are:

2, 3 and 5

Number of favourable outcomes = 3

∴ P(E) $=\dfrac{Number of favourable outcomes}{Total number of possible outcomes}$

$=\dfrac{3}{6}$

$=\dfrac{1}{2}$

Hence, $P(E)=\dfrac{1}{2}$