find the probability of Sundays in a leap year
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there will be 52 Sundays
Angelaniya2018:
i think this is in correct
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Answer:
Step-by-step explanation:
A normal year has 52 Mondays, 52 Tuesdays, 52 Wednesdays, 52 Thursdays, 52 Fridays, 52 Saturdays, 52 Sundays and +1 day that could be anything depending upon the year under consideration.
In addition to this, a leap year has an extra day which might be Monday or Tuesday or Wednesday or Thursday or Friday or Saturday or Sunday.
Therefore, our sample space is S :( Monday - Tuesday, Tuesday -
Wednesday - Wednesday - Thursday, Thursday - Friday, Friday - Saturday, Saturday - Sunday, Sunday - Monday)
n(S) =7
What we want in set A that contains the elements which is pair with Sunday.
Therefore, A=(Saturday - Sunday, Sunday - Monday)
n(A) =2
P(A)=n(A)/n(S)=2/7
Therefore, Probability is 2/7
read the question carefully
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