find the probability of the following
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Probability= Total no. of events/ No. of favorable events
1. (I) There are 4 red disc so the probability of getting red disc is 4/3
(ii) There are 2 yellow disc so the probability of getting yellow disc is 2/4 or 1/2
(III) There are 3 blue disc so the probability of getting blue disc is 3/3 or 1
2) A leap year has 366 days and 52 weeks and 2 odd days Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So the probability of getting Sundays is 2/7
3) When two dices are thrown the total probabilities are 36 so:
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3)(6,4)(6,5),(6,6)) the probability of getting a sum of 10 is 3/10
1. (I) There are 4 red disc so the probability of getting red disc is 4/3
(ii) There are 2 yellow disc so the probability of getting yellow disc is 2/4 or 1/2
(III) There are 3 blue disc so the probability of getting blue disc is 3/3 or 1
2) A leap year has 366 days and 52 weeks and 2 odd days Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So the probability of getting Sundays is 2/7
3) When two dices are thrown the total probabilities are 36 so:
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3)(6,4)(6,5),(6,6)) the probability of getting a sum of 10 is 3/10
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Hope this helps you ☺️☺️
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