Question

Find the probability of the following event if a coin is tossed three times 1) Get a tail at least once 2) More than twice the head 3) Get the head exactly twice
please do not give wrong answer​ because these question is very important​

Answer 1

Answer:

Sample space: {

HHH,HTH,THH,TTH

HHT,HTT,THT,TTT

}

Total number of possible outcomes=8

(1) A getting at least two heads

P(A)=P(getting two heads)+P(getting 3 heads)

=

83+ 81

(using formula=P(event)=

Total no. of possible outcomes

No. of favourable outcomes

P(A)=

84 =

21

∴P(A)=

21

(2) B: getting exactly two heads

P(B)=3/8

(3) C: getting almost one head

P(C)=P(getting no head)+P(getting 1 head)

= 81 + 83

= 84 = 21

P(C)=

21.