Question

Find the probability of the following event if two aspects are bounced together 1) Find different numbers on both sides 2) The sum of the digits on both sides is 7 3) Get odd digits on both sides

 by method​

Answer 1

Probability of an event = Number of outcomes favourable to that event/ Number of all possible outcomes.

The set of all possible outcomes is called the sample space and is denoted by S.

When two dice are tossed, the possible outcomes are (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6). Hence n(S) = 36.

But we want the desired event E that the number should be same on both dice. Such outcomes (1,1),(2,2),(3,3)(4,4),(5,5) and (6,6). We have 6 desired outcomes. So n(E) = 6

Hence the probability of getting same number. on both dice = n(E)/ n(S) = 6/36 = 1/6