find the probability of the occuence of on a die if the has one more of its facs marked as 1 instead of 6
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Different scores that are possible as a combination of both dices are thrown -
(0,0) = 0
(0,1) = 1
(0,6) = 6
(1,1) = 2
(1,6) = 7
(6,6) = 12
To get a score of 7, one dice must show 1 and one dice must show 6.
Probability of dice getting 1 = 3/6 = 1/2.
Probability of dice getting 6 = 2/6 = 1/3.
Thus probability of getting score 7 is =
1/2 * 1/3 + 1/2*1/3 = 1/3.
Hope this helps you☺
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