find the probability of throwing a head or tail alternatively in 3successive tossing of a coin
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Answer:
= h=4/6, t=2/6 or h=2/6, t=4/6
= h=5/6, t=1/6 or h=1/6, t=5/6
= h=0/6, t=6/6 or h=6/6, t=0/6
Step-by-step explanation:
One time tossing of the coin (p)
= head=1/2, tails=1/2
= h=2/2, t=0/2 or h=0/2, t=2/2
Two time tossing of the coin (p)
= head=2/4, tails=2/4
=h=3/4, t=1/4 or h=1/4, t=3/4
=h=4/4, t=0/4 or h=0/4, t=4/4
Three time tossing of the coin (p)
= head=3/6, tails=3/6
= h=4/6, t=2/6 or h=2/6, t=4/6
= h=5/6, t=1/6 or h=1/6, t=5/6
= h=0/6, t=6/6 or h=6/6, t=0/6
Therefore,
The probability of throwing a head or tail alternatively in 3successive tossing of a coin
= h=3/6, t=3/6
= h=4/6, t=2/6 or h=2/6, t=4/6
= h=5/6, t=1/6 or h=1/6, t=5/6
= h=0/6, t=6/6 or h=6/6, t=0/6.
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