Question

Find the probability of throwing a sum 9 with two dice

Answer 1

getting this event:

A={(3,6),(4,5),(5,4),(6,3)}

n(A)=4

n(S)=36

p(A)=n(A)/n(S)

=4/36

=1/9

Answer 2

The probability of throwing a sum 9 with two dice is $\frac{1}{9}$.

Step-by-step explanation:

To find : The probability of throwing a sum 9 with two dice?

Solution :  

When two dice are thrown,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

The favorable outcome is getting a sum 9 i.e. {(3,6),(4,5),(5,4),(6,3)}= 4

Total number of outcome = 36

The probability of sum 9 is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}$

$\text{Probability}=\frac{4}{36}$

$\text{Probability}=\frac{1}{9}$

#Learn more  

If two dice are thrown simultaneously, then the probability of getting a doublet or a total of 6 is

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