Math, asked by abhishekchaugai7663, 10 months ago

Find the probability that a leap year chosen at random will contain 53 sundays.
1. 2/7
2. 3/7
3. 1/49
4. 1/7

Answers

Answered by anitaphadatare30433
1

Answer:

Step-by-step explanation:

1] 2/7

Do u need any explanation regarding the question?

Answered by Anonymous
68

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Correct option: (4.)

A non-leap year has 365 days.

365 days = 52 weeks + 1 day

Since 52 weeks = 52 x 7 = 364 days

Hence there will be 52 Sundays in a year.

This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or Sunday.

Out of these total 7 outcomes, the number of favourable outcomes is 1.

Hence, the probability of getting 53 Sundays = 1 / 7

Hope it's Helpful.....:)

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