Question

find the probability that a leap year contains 53 sundays?

Answer 1

There are 366 days in a leap year. So there will be 52 complete weeks and 2 days.
The 2 days can be any two consecutive days of the week:
Sample space is:

Sunday and Monday
Monday and Tuesday
Tuesday and Wednesday
Wednesday and Thursday
Thursday and Friday
Friday and Saturday
Saturday and Sunday

There are total 7 possibilities and number of possibility of Sunday is 2.
Probability of 53rd Sunday = 2/7

Answer 2

Leap Year has 366 days, den
weeks= 52
Sundays= 52
and 2 days remaining.

Den, the 2 days can be any of the following like >>>>>>>
⇒ Sunday and Monday 
⇒ Monday and Tuesday 
⇒ Tuesday and Wednesday 
⇒ Wednesday and Thursday 
⇒ Thursday and Friday 
⇒ Friday and Saturday 
⇒ Saturday and Sunday 

Therefore Probablity will be......

⇒n(S) = 7 
⇒n(E) = 2 
⇒P(E) = n(E) / n(S) = 2 / 7