Question

find the probability that a leap year selected at random will contain 53 sundays?​

Answer 1

Answer:

Its probability will be 2/7

Step-by-step explanation:

In a leap year no of odd days are 2

these can be

(mon,Tue)(Tue,Wed)(Wed,Thu)(Thu,Fri)(Fri,Sat)(Sat,Sun)(Sun,Mon)

Total case =7

Favourable case =2

probability of event=2/7

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Answer 2

Answer:

In a leap year there are 366 days. In 366 days, we have 522 weeks and 2 days, Thus we can say that leap year ah always 52 Sundays.

The remaining two days can be :

(i) Sunday and Mondays

(ii) Mondays and Tuesdays

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(vi) Friday and Saturday

(vii) Saturady and Sunday.

From above it is clear that there are 7 elementary events associated with this random experiment.

Clearly the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.

∴ P (E) = n (E)/n (S) = 2/7