. Find the probability that a leap year selected at random will contain 53 Sundays
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A leap year = 366 days .
More precisely
366 days = 52 weeks and 2 days
Thus, a leap year has always 52 Sundays.
The remaining 2 days can be:
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday.
Let A be the event that a leap year has 53 Sundays.
Clearly, the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.
Total favourable cases = 7
∴ Favourable number cases for A event = 2
So the required probability = 2/7
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