find the probability that a leap year selected at random will contain 53 Sundays
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A leap year has 366 days
It means 366/7=52.2 or 52 weeks and 2 days
So in 52 weeks there will be 52 sundays but remaining two days can be( Monday Tuesday),( Tuesday Wednesday), (Wednesday Thursday)
( Thursday Friday),( Friday Saturday) (Saturday Sunday),(sunday Monday)
So in total 7 pairs .2 pairs have sunday( Saturday Sunday ,Sunday Monday)
So probability will be 2/7
It means 366/7=52.2 or 52 weeks and 2 days
So in 52 weeks there will be 52 sundays but remaining two days can be( Monday Tuesday),( Tuesday Wednesday), (Wednesday Thursday)
( Thursday Friday),( Friday Saturday) (Saturday Sunday),(sunday Monday)
So in total 7 pairs .2 pairs have sunday( Saturday Sunday ,Sunday Monday)
So probability will be 2/7
sakura2121:
Thanks for making my answer brainliest
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1
a leap year has 366 days and 364 days make 52 weeks.therefore ew have have to find the probability of having sunday out of the remaining 2 days
p(having 53 sundays)=2/7
p(having 53 sundays)=2/7
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