Find The probability that a leap year selected at random will contain 53 sundays
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Answered by
7
7÷366= 52+2days
therefore p=2/7
therefore p=2/7
Answered by
15
an ordinary year consists of 365 days
ie. 52 weeks n 1 day
but in case of a leap year, there are 366 days.. thus, 52 weeks n 2 days..
so these two days may be (Sunday, Monday) ( Monday, Tuesday) ( Tue, wed) (wed.,Thu) ( Thu, fri) (Fri, sat) (sat, Sun)
so the probability is 2/7
hope that helps! :)
ie. 52 weeks n 1 day
but in case of a leap year, there are 366 days.. thus, 52 weeks n 2 days..
so these two days may be (Sunday, Monday) ( Monday, Tuesday) ( Tue, wed) (wed.,Thu) ( Thu, fri) (Fri, sat) (sat, Sun)
so the probability is 2/7
hope that helps! :)
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