Find the probability that a leap year selected at random will contain 53 Wednesday or Friday.
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The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.Feb 20, 2018
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