Find the probability that a leap year, selected at random will contain 53 Sundays?...
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Step-by-step explanation:
The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.
So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is 2/7
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