Find the probability that a leap year selected at random ,will contain 53 Sundays.
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Answered by
33
Total no. of days in leap year =366
so total no. of complete week =52
Days left =336-52×7
=336-334
=2
2days can be :
Sunday and Monday
Monday and Tuesday
Tuesday and Wednesday
Wednesday and Thursday
Thursday and Friday
Friday and Saturday
Saturday and Sunday
so,there is two possibility in which Sunday came
so P(Sunday)= 2/7
so total no. of complete week =52
Days left =336-52×7
=336-334
=2
2days can be :
Sunday and Monday
Monday and Tuesday
Tuesday and Wednesday
Wednesday and Thursday
Thursday and Friday
Friday and Saturday
Saturday and Sunday
so,there is two possibility in which Sunday came
so P(Sunday)= 2/7
mahesh9836:
thanks
Answered by
8
Therefore,the probability of that a leap year selected at random,will contain 53 Sundays is 2/7.
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