Question

find the probability that a leap year selected at random will contain 53 Sunday

Answer 1

For leap year 366 days. days are converted to week.

366=(7*52)+2=364+2

so 52 weeks and remaining two days.

for two days may be

Sunday and Monday

Monday and Tuesday

Tuesday and Wednesday

Wednesday and Thursday

Thursday and Friday

Friday and Saturday

Saturday and Sunday

2 Sundays are coming.

therefore the probability of 53 Sundays for Leap-year = 2/7


Hope it helps:)
Mark brainliest

Answer 2

Answer:

In a leap year there are 366 days. In 366 days, we have 522 weeks and 2 days, Thus we can say that leap year ah always 52 Sundays.

The remaining two days can be :

(i) Sunday and Mondays

(ii) Mondays and Tuesdays

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(vi) Friday and Saturday

(vii) Saturady and Sunday.

From above it is clear that there are 7 elementary events associated with this random experiment.

Clearly the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.

∴ P (E) = n (E)/n (S) = 2/7