find the probability that a leap year selected at random will contain53 sundays
Answers
Answered by
2
As total number of Sundays will be 365/7
So there will be 52 sundays
Confirmed hence probability will
Be 2/7
So there will be 52 sundays
Confirmed hence probability will
Be 2/7
Answered by
0
Answer:
In a leap year there are 366 days. In 366 days, we have 522 weeks and 2 days, Thus we can say that leap year ah always 52 Sundays.
The remaining two days can be
(i) Sunday and Mondays
(ii) Mondays and Tuesdays
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(VI) Friday and Saturday
(vii) Saturady and Sunday.
From above it is clear that there are 7 elementary events associated with this random experiment.
Clearly the event A will happen if the last two days of the leap year are either Sunday and Monday or Saturday and Sunday.
∴ P (E) = n (E)/n (S) = 2/7
Similar questions