find the probability that a leap year selected at rendom will contain 53 sunday
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Answered by
2
No. of days in a leap year = 366
No. of Sundays = 53
P(No. of Sundays in a leap year) = 53/366
Sorry this is wrong
No. of Sundays = 53
P(No. of Sundays in a leap year) = 53/366
Sorry this is wrong
kunaltatwal10:
average
i think your answer is incorrect...
what will be the right answer pls let me know
i have solved this and posted u can refer from there...
ur wlcm
Answered by
3
A leap year has 366 days, i.e, 52 weeks and 2 days.
Now the remaining 2 days can be
• Monday, Tuesday
• Tuesday, Wednesday
• Wednesday, Thursday
• Thursday, Friday
• Friday, Saturday
• Saturday, Sunday
• Sunday, Monday
Now the total outcomes = 7
the favourable outcomes=2 (Sunday,Monday and Saturday, Sunday)
So, P( one of the remaining 2 days is Sunday)=2/7
The probability that a leap year has 53 Sundays is 2/7...
✨HOPE THIS ANSWER HELPS YOU✨
Now the remaining 2 days can be
• Monday, Tuesday
• Tuesday, Wednesday
• Wednesday, Thursday
• Thursday, Friday
• Friday, Saturday
• Saturday, Sunday
• Sunday, Monday
Now the total outcomes = 7
the favourable outcomes=2 (Sunday,Monday and Saturday, Sunday)
So, P( one of the remaining 2 days is Sunday)=2/7
The probability that a leap year has 53 Sundays is 2/7...
✨HOPE THIS ANSWER HELPS YOU✨
Ok thank you
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