Find the probability that a leap year should have 53 Tuesdays
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A leap year has 366 days
on divided it by 7 remainder is 2
so possibility for two days is
sunday, monday
mon. ,tues.
tues., wed.
wed., thursday
thur., fri.
fri., sat
sat., sun.
posiible outcomes 7
favourable tuesday cases 2
prob. 2/7
on divided it by 7 remainder is 2
so possibility for two days is
sunday, monday
mon. ,tues.
tues., wed.
wed., thursday
thur., fri.
fri., sat
sat., sun.
posiible outcomes 7
favourable tuesday cases 2
prob. 2/7
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