Math, asked by dharamveer12865, 2 months ago

Find the probability that a non-bap year . chosen at random has? 0 ' 18 Sundays I 오 52 Sundays

Answers

Answered by xAWMx

In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.

Answered by gaurianushka987

Answer:

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