Find the probability that a non leap year chosen at random has i) 52 Sundays. ii) 53 Sundays
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Answered by
187
Answer:
Step-by-step explanation:
A non-leap year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364 days .
365– 364 = 1day extra.
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 sundays = 1 / 7.
∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7.
Answered by
3
Answer:
in a non leap year there will be 52 Sundays
- 365 days is =52 weeks and one day
- total of outcome from 1 day
- total number of day in week is =7
- from Sunday outcome is 1
- total probability 1/ 7
- not Sunday 1 - 1 / 7
- 7 /7- 1 / 7 = 6 /7
2. 53 Sunday is Sunday 1/ 7
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