Find the probability that a non-leap year chosen at random has (1) 52 Sundays
(2) 53 Sundays.
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Answer:
days in non leap year = 365 = 52 weeks & 1 day.
if this 1 day is not Sunday then the year will have 52 Sundays.
hence probability of 52 Sunday is = 6/7.
therefore probability of 53 Sunday is = 1/7. (when the 1 day is Sunday).
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