Math, asked by Anonymous, 1 year ago

find the probability that a non leap year selected at random will have 53 tuesdays

pls pls solve it
very very urgent...........

Answers

Answered by Swebo
3
A non-leap year has 365 days or 52 weeks and 1 odd day. The odd day can be Sunday,Monday, Tuesday,Wednesday,Thursday,Friday or Saturday. So there are 7 possibilities out of which 1 is favorable. So the probability of 53 Tuesdays in non-leap year is 1/7.

Anonymous: thnxx #swebo
Swebo: Mention not buddy
Answered by 12391
1
A leap year 366/7 week's ,i.e.52 weeks & 2day
it maybe (Sunday ,Monday) , (Monday ,Tuesday) ,(Tuesday ,Wednesday) ,(Wednesday ,thrusday),(thrusday ,Friday ),(Friday ,Saturday) ,(satuday,sunday)
the probability of getting Tuesday is 2/3.

Anonymous: that's not my question's answer
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