Question

Find the probability that a non leap year selected at random will contain 53 sunday

Answer 1

Answer:

1/7

Step-by-step explanation:

We know that A non-leap year consists of 365 days.

In 365 days, Number of weeks = 52 and 1 day remaining.

For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.

Out of these 7 total outcomes, the favorable outcomes are 1.

Hence the probability of getting 53 Sundays = 1/7

Answer 2

Answer:

A non leap year contain 365 days and a week contain 7 days so if we divide 365÷7 then the remainder will be 1 and the questiont will be 52 so it means only 1 day will remain at the last of the year and it can be any day so we will consider it Sunday so 52 weeks means 52 Sunday and the 1 more day = 53 sunday