Math, asked by jalpabrava, 5 months ago

Find the probability that a number selected at
random from the numbers 1, 2, 3 ... 35 is a
Prime number Multiple of 7 multiple of 3or5​

Answers

Answered by pzone12
0

Answer:

ANSWER

Solution(i):

Let E be event of getting a prime number from the list of numbers 1 to 35

Prime nos. upto 35=2,3,5,7,11,13,17,19,23,29,31

No. of favorable outcomes=11

Total no. of possible outcomes =35

We know that, Probability P(E) =(Total no.of possible outcomes)(No.of favorable outcomes)=3511

Therefore, the probability that a prime number is selected from the numbers 1,2,3,.......,35 is 3511

Solution(ii):

Let F be event of getting a multiple of 7 from the numbers 1 to 35

Multiples of 7 upto 35=7,14,21,28,35

No. of favorable outcomes=5

Total no. of possible outcomes =35

We know that, Probability P(F) =(Total no.of possible outcomes)(No.of favorable outcomes)=355=71

Therefore, the probability that a number selected from the numbers 1,2,3,.......,35 is a multiple of 7 is 71

Solution(iii):

Let G be event of getting a multiple of 3 or 5 from the numbers 1 to 35

Multiples of 3 or 5 upto 35=3,5,6,9,10,12,15,18,20,21,24,25,27,30,33,35

No. of favorable outcomes

Step-by-step explanation:

ANSWER

Solution(i):

Let E be event of getting a prime number from the list of numbers 1 to 35

Prime nos. upto 35=2,3,5,7,11,13,17,19,23,29,31

No. of favorable outcomes=11

Total no. of possible outcomes =35

We know that, Probability P(E) =(Total no.of possible outcomes)(No.of favorable outcomes)=3511

Therefore, the probability that a prime number is selected from the numbers 1,2,3,.......,35 is 3511

Solution(ii):

Let F be event of getting a multiple of 7 from the numbers 1 to 35

Multiples of 7 upto 35=7,14,21,28,35

No. of favorable outcomes=5

Total no. of possible outcomes =35

We know that, Probability P(F) =(Total no.of possible outcomes)(No.of favorable outcomes)=355=71

Therefore, the probability that a number selected from the numbers 1,2,3,.......,35 is a multiple of 7 is 71

Solution(iii):

Let G be event of getting a multiple of 3 or 5 from the numbers 1 to 35

Multiples of 3 or 5 upto 35=3,5,6,9,10,12,15,18,20,21,24,25,27,30,33,35

No. of favorable outcomes

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