Question

Find the probability that a number selected at random from the numbers 1, 2, 3, ...., 35 is divisible by 2 and 3 both

step by step answer will be marked as brainliest​

Answer 1

Answer:

$\frac{1}{7} | is \: the \: answer$

Step-by-step explanation:

S={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21, 22,23,24,25,26,27,28,29,30,31,32,33,34,35}

let A be the event that the number selected is divisible by 2 and 3

A={6,12,18,24,30}

n(A)=5

P(A)=

$\frac{n(a)}{n(s)}$

=

$\frac{5}{35}$

=

$\frac{1}{7}$