Math, asked by manjusree003, 6 months ago

Find the probability that a number selected from numbers 1, 2, 3,..., 20 is a prime number, when each of the given numbers is equally likely to be selected?​

Answers

Answered by zkapoor
2

Answer:

S={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,1920}

n(S) = 20

Event: The Prime Numbers

A={2, 3, 5, 7, 11, 13, 17, 19}

n(A)= 7

P(A) = n(A) /n(S)

= 7/20

Answered by pruthaasl
0

Answer:

The probability that the number is prime is 0.4

Step-by-step explanation:

It is given that a number is selected from numbers 1, 2, 3, ... , 20.

Therefore, the sample space will be

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}

n(S) = 20

Let A be the event of selecting a number from the sample space.

We have to find the probability that the selected number is a prime number. Therefore,

A = {2, 3, 5, 7, 11, 13, 17, 19}

n(A) = 8

The probability is given as follows:

P(A) = n(A) / n(S)

Substituting the values, we get

P(A) = 8/20

P(A) = 0.4

Therefore, the probability that a number selected from numbers 1, 2, 3,..., 20 is a prime number is 0.4

#SPJ3

Similar questions