Find the probability that a randomlychosen number from 1.To 12 is a divisor of 12
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Answer:
Step-by-step explanation:
From 1 to 12 no. are 1,2,3,4,5,6,7,8,9,10,11,12.
From the list, two no. are divisor of 12
That is 6&12. So, probability of getting a divisor of 12=
P(E)= total divisor of 12 from given list/total list of numbers
Therefore,
P(E) =2/12=1/6
Hence probability of getting a divisor of 12 from 1 to 12 is 1/6.
Thank you.....
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