Find the probability that an odd number turns up in a single throw of a die?
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Answer:
Total possible outcomes on throwing a die={1,2,3,4,5,6}
∴ Total number of cases =6
Favourable cases ={1,3,5}
Number of favourable cases =3
Probability P(E)=
Total number of cases
Number of favourable cases
P(E)=
6upon
3
P(E)=
2 upon
1
Step-by-step explanation:
hope it helps you
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