Question

Find the probability that in 120 tosses of a fair coin , a) Between 40% and 60% will be heads
b) 5/8 or more will be heads

Answer 1

Answer:48 and 72 and b is 75

Step-by-step explanation:

Answer 2

The $120$ tosses of aa fair coin $0.9779.$

Step-by-step explanation:

Because of binomial probability we have,

$P(K)=(120)(\frac{1}{2})^{K}(\frac{1}{2})^{120-K$

$=(120)_{K}(\frac{1}{2})^{120$

∑$(120)_K(\frac{1}{2})^{120}$

≈.9779.