Question

find the probability that leap year selected at random will contain 53 ​

Answer 1

Step-by-step explanation:

The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday},{Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}. So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays is 2/7.Feb 20, 2018

Answer 2

Answer:

2/7

Step-by-step explanation:

A leap year has 366 days which means 52 weeks and 2 extra days

That means 52 Sundays and two extra days

If one of the two days is Sunday the year will have 53 Sundays

Thus S = {(Sunday , Monday) , (Monday , Tuesday)

, (Tuesday , Wednesday) , (Wednesday,

Thursday) , (Thurs , Fri) , (Fri , Sat) , (Sat , Sun)

n(S) = 7

probability is one of the days is Sunday

thus A = {(Sun , Mon) , (Sat , Sun)}

n(A) = 2

Thus , P(A) = 2/7