Math, asked by mithparekh0817, 1 month ago

Find the probability that their are 53 saturdays in a year which is not a leap year. A year which is not a leap year has 365 days.​

Answers

Answered by sahaarnab828
1

Answer:

0.14 or 1/7 is probability for 53 Saturdays in a non-leap year

Step-by-step explanation:

Workout

step 1 Possible events for 1 odd day

The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.

step 2 Probability of 1 Odd day to be Saturday :

The sample space S = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

Expected event of A = {Saturday}

P(A) =

{Saturday}{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

P(A) = 1/7

P(A) = 0.14

0.14 or 1/7 is probability for 53 Saturdays in a non-leap year

Answered by Anonymous
4

Answer:

first learn to write English

your English is weak

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