Find the probability that their are 53 saturdays in a year which is not a leap year. A year which is not a leap year has 365 days.
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Answered by
1
Answer:
0.14 or 1/7 is probability for 53 Saturdays in a non-leap year
Step-by-step explanation:
Workout
step 1 Possible events for 1 odd day
The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.
step 2 Probability of 1 Odd day to be Saturday :
The sample space S = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}
Expected event of A = {Saturday}
P(A) =
{Saturday}{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}
P(A) = 1/7
P(A) = 0.14
0.14 or 1/7 is probability for 53 Saturdays in a non-leap year
Answered by
4
Answer:
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