Question

find the probability that three numbers chosen at random from first nine natural numbers from an AP?????

Answer 1

Natural no are=1,2,3,4,5,6,7,8,9 Random no=1,3,5 P(getting random no)=total number of random /total number . =3/9=1/3.is your answer

Answer 2

Sol :- ⇒No .of Natural numbers = 1,2,3,4,5,6,7,8, 9... ⇒ No.of random numbers = 1,3,7..... ⇒ P( First nine numbers from an AP ) = Total.No.of . Random numbers / Total. No.of natural numbers.... ⇒ 3/9 = 1/3 is the answer !