Question

Find the probable error if r=2/√10 and n = 36.
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Answer 1

Answer:

The Probable Error of r=2/√10 and n = 36 is 0.06745

Step-by-step explanation:

From the above question they have given

r = 2/√10

n = 36

In statistics, in all like  error defines the half-range of an interval about a central factor for the distribution, such that half of of the values from the distribution will lie inside the interval and 1/2 outside.

To find the Probable Errowe have the formula.

   Probable Error = 0.674 × \( \frac{1-r^2}{√N} \)

Assume that the correlation coefficient is 0.8 and the pairs of samples are 25. Therefore, the likely error is: 0.0486. Question: If the fee of r = 0.7 and that of n = 64, then discover the P. E. of the correlation of coefficient.

P.E r = 0.6745  ($\frac{(1-r^2)}{\sqrt{n} }$)

        = 0.6745 ($\frac{(1-(\frac{2}{\sqrt{10} } )^2)}{\sqrt{36} }$

Probable Error = 0.06745

Hence the Probable Error of r=2/√10 and n = 36 is 0.06745.

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