Math, asked by 268850, 4 months ago

find the probablity of finding 53 sundays in orinary​

Answers

Answered by Anonymous
15

Answer:

For 52 weeks, There will be 52 Sundays. The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday. Out of these 7 total outcomes, the favorable outcomes are 1. Hence the probability of getting 53 Sundays = 1/7.

Answered by Anonymous
1

Non-leap year = 365 days

In 365 days, Number of weeks = 52 weeks and 1 day is remaining.

For 52 weeks number of Sundays = 52

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Total of 7 outcomes, the favourable outcome is 1.

∴ probability of getting 53 Sundays = \sf\dfrac{1}{7} .

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