find the probablity of having 53 Sunday in (1) a leap year (2) non leap year
Answers
Answered by
2
hiii..this is your answer
Attachments:
Answered by
3
No of weeks in a year is 52
1 week 7 days
So total days is 52×7 = 364
In case of a non leap year only 1 day remain extra
In a leap year only 2 days remain extra
1) in a non leap year chances of 53 sunday is 1/7
As only 1 day remain extra out of a week
2) in a leap year chances of 53 sunday is 2/7
As only 2 days remain extra out of 7 days in a week
1 week 7 days
So total days is 52×7 = 364
In case of a non leap year only 1 day remain extra
In a leap year only 2 days remain extra
1) in a non leap year chances of 53 sunday is 1/7
As only 1 day remain extra out of a week
2) in a leap year chances of 53 sunday is 2/7
As only 2 days remain extra out of 7 days in a week
STORMSUNIL:
I request u to mark my answer as brainliest answer
Please mark It as brainliest answer
I request u
Please do it
Similar questions