Question

find the product: (0.4x+0.5y) (0.16x^2-0.2xy+0.25y^2)

Answer 1

Answer:

0.064x^3-0.08x^2y-0.1xy^2+0.125y^3

EXPLANATION:

(0.16x^2-0.2xy+0.25y^2) = (0.4x-0.5y)^2

(0.4x+0.5y) (0.4x-0.5y) (0.4x-0.5y)=

{ (0.4x)^2 -(0.5y)^2 } (0.4x-0.5y)=

(0.16x^2 - 0.25y^2) (0.4x-0.5y)=

0.064x^3 - 0.08x^2y - 0.1xy^2+0.125y^3

Please make me the Brainliest