Math, asked by moizlalji786, 10 months ago

Find the product
1. (2/3xy) ×(-9/10x upon 2 y upon 2)

Answers

Answered by veerendrakumaruppu
12
(2/3xy) x ((-9/10x)/2y/2)

= (2/3xy) x ((-9/10x)*(2/2y))

= (2/3xy) x ((-9/10x)*(1/y))

= (-3/5)*(1/xy)*(1/xy)

= (-3/5)*(1/x^2*y^2)

= -3/(5* x^2*y^2) ——> Answer
Answered by sagarrohan549
0

Answer:

gtvdgujiojfvfghkpggh

Similar questions