Question

find the product (-1/27a^2b^2)×(-9/5a^3b^2c)​

Answer 1

Step-by-step explanation:

The variable part in the product of two monomials is equal to the product of the variables in the given monomials. Then, = [(-1/27) × (-9/2)] × (a2 × a3) × (b2 × b) × c2 = [(-1×-9)/ (27×2)] × (a2+3) × (b2+1) × c2 … [∵ am × an = am+n] = [(-1×-1)/ (3×2)] × (a5) × (b3) × c2 = [1/6]a5b3c2Read more on Sarthaks.com - https://www.sarthaks.com/748526/1-27-a-2b-2-9-2-a-3bc-2