Question

Find the product

1) 2xy(4xy-3yz+6xz)
2)(3a-7b) (2a-6b+c)
3)(2p+3q) ²
4)(3x-4y) ²
5)101² solve by using identify (a+b) ²=a²+2ab+b²
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Answer 1

1)2xy(4xy−3yz+6xz)

=(2xy)(4xy+−3yz+6xz)

=(2xy)(4xy)+(2xy)(−3yz)+(2xy)(6xz)

=8x2y2−6xy2z+12x2yz

=8x2y2+12x2yz−6xy2z

2)(3a−7b)(2a−6b+c)

=(3a+−7b)(2a+−6b+c)

=(3a)(2a)+(3a)(−6b)+(3a)(c)+(−7b)(2a)+(−7b)(−6b)+(−7b)(c)

=6a2−18ab+3ac−14ab+42b2−7bc

=6a2−32ab+3ac+42b2−7bc

3) (2p+3q)2

=(2p+3q)(2p+3q)

=(2p)(2p)+(2p)(3q)+(3q)(2p)+(3q)(3q)

=4p2+6pq+6pq+9q2

=4p2+12pq+9q2

4)(3x−4y)2

=(3x+−4y)(3x+−4y)

=(3x)(3x)+(3x)(−4y)+(−4y)(3x)+(−4y)(−4y)

=9x2−12xy−12xy+16y2

=9x2−24xy+16y2

5) don't know this answer

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