Math, asked by ayazmuhammedponni, 1 year ago

Find the product
(1/5x - 1/3y) (1/5x-1/7y)

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HEMANTHKUMAR007: Mark It as brainliest answer

Answers

Answered by HEMANTHKUMAR007
2
\underline{\mathfrak{\huge{Answer}}}

= ({\huge{\frac{x}{5}}} - {\huge{\frac{y}{3}}} )({\huge{\frac{x}{5}}} - {\huge{\frac{y}{7}}})

= ( {\huge{\frac{3x - 5y}{15}}})( {\huge{\frac{7x - 5y}{35}}})

= {\huge{\frac{21x^2 - 15xy - 35xy + 25y^2 }{525}}}

= {\huge{\frac{21x^2 - 40xy + 25y^2}{525}}}

Hence, This is the \underline{\mathfrak{\huge{Answer}}}

(OR)


= {\huge{\frac{21x^2 - 35xy - 15xy + 25y^2 }{525}}}

= {\huge{\frac{7x(3x - 5y) - 5y(3x - 5y)}{525}}}

= {\huge{\frac{(3x - 5y)( 7x - 5y)}{525}}}

\underline{\mathfrak{\huge{Thank You}}}

ayazmuhammedponni: Exactly wrong
HEMANTHKUMAR007: why
HEMANTHKUMAR007: it's 50xy
HEMANTHKUMAR007: sorry
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