Question

find the product... (1/5xy + 3/4y^2 ) (10xy - 8/3y^3) explain with solutions.​

Answer 1

Answer:

Step-by-step explanation:

$(\dfrac{1}{5}xy+\dfrac{3}{4}y^{2})(10xy-\dfrac{8}{3}y^{3})=\dfrac{1}{5}xy*(10xy-\dfrac{8}{3}y^{3})+\dfrac{3}{4}y^{2}*(10xy-\dfrac{8}{3}y^{3})$

                                      $=(\dfrac{1}{5}xy*10xy) - (\dfrac{1}{5}xy*\dfrac{8}{3}y^{3})+(\dfrac{3}{4}y^{2}*10xy)- (\dfrac{3}{4}y^{2}*\dfrac{8}{3}y^{3})\\\\\=2x^{2}y^{2}-\dfrac{8}{15}xy^{4}+\dfrac{15}{2}xy^{3}-2y^{5}$

Answer 2

Step-by-step explanation:

find the product... (1/5xy + 3/4y^2 ) (10xy - 8/3y^3)