Find the product (13y²z)(2xyz²)
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1
Answer:
=(2x−y+3z)(4x
2
+y
2
+9z
2
+2xy+3yz−6xz)
=(a+b+c)(a
2
+b
2
+c
2
−ab−bc−ac)
=a
3
+b
3
+c
3
−3abc
=(2x)
3
+(−y)
3
+(3z)
3
−3.(2x)(−y)(3z)
=8x
3
−y
3
+27z
3
+18xyz
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