Find the product (2/3) abc ( a^2 + b^2 - 3c^2)
Answers
Answered by
0
answer :
C
Solution :
(3a+2b+3c)2-(2a+3b+2c)2+5b2
=(3a+2b+3c+2a+3b+2c)(3a+2b+3c-2a-3b-2c)+5b2
=(5a+5b+5c)(a-b+c)+5b2
=5(a+c+b)(a+c-b)+5b2
=5[(a+c2)-b2]+5b2
=5(a+c)2
∴ Square root of the given expression is
√
5(a+c)2
=
√
5
(a+c)
Answered by
0
Answer:
The answer is (2by 3abc 3
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