Question

find the product (2/3xy)×(-9/10x2y2)​

Answer 1

2/3xy*-9/10x2y2

-18/30x3y3

-9/15x3y3

-3/5x3y3

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Answer 2

The product is

$= - \frac{3}{5 {x}^{3} {y}^{3} }$

GIVEN:-

$\frac{2}{3xy} \times ( - \frac{9}{10 {x}^{2} {y}^{2} } )$

TO FIND:- product

SOLUTION:-

• Product of two numbers is the multiplication or time of two numbers.
• Product of a negative integer and positive integer is always positive.

$\frac{2}{3xy} \times - \frac{9}{10 {x}^{2} {y}^{2} }$

When we multiply powers which has same base then the powers are added like x × x² = x³ and y × y² = y³

We'll multiply the coefficients

$= - \frac{18}{30 {x}^{1 + 2} {y}^{1 + 2} } \\ = - \frac{18}{30 {x}^{3} {y}^{3} }$

We'll reduce the fraction by dividing numerator and denominator by 6,

$= - \frac{18 \div 6}{30 {x}^{3} {y}^{3} \div 6 } \\ = - \frac{3}{5 {x}^{3} {x}^{3} }$

Hence, the product is

$= - \frac{3}{5 {x}^{3} {y}^{3} }$

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