Math, asked by harshitsri1309, 1 month ago

find the product:-
(2a-1/2a)(2a+1/2a)(4a2+1/4a2)(16a4+1/16a4)​

Answers

Answered by vikasjioasus
1

Hope this will help you.

Attachments:
Answered by bagkakali
1

Answer:

(2a-1/2a)(2a+1/2a)(4a^2+1/4a^2)(16a^4+1/16a^4)

={(2a)^2-(1/2a)^2}(4a^2+1/4a^2)(16a^4+1/16a^4)

=(4a^2-1/4a^2)(4a^2+1/4a^2)(16a^4+1/16a^4)

={(4a^2)^2-(1/4a^2)}(16a^4+1/16a^4)

=(16a^4-1/16a^4)(16a^4-+1/16a^4)

=(16a^4)^2-(1/16a^4)^2

=256a^4+1/256.a^4

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