Math, asked by Prakarshan, 3 months ago

find the product ( 2a + b + c ) ( 4a² + b² + c² - 2ab - bc - 2ca )

i need it

Answers

Answered by CopyThat
14

Given :-

➔ ( 2a + b + c ) ( 4a² + b² + c² - 2ab - bc - 2ca )

To find :-

➔ Their Product

Solution :-

➔  ( 2a + b + c ) ( 4a² + b² + c² - 2ab - bc - 2ca )

➔  ( 2a + b + c ) ( 2a² + b² + c² - (2a)(b) - (b)(c) - (c)(2a)

➝  ( x + y + z ) ( x² + y² + z² - zy) :- x³ + y³ + z³ - 3xyz

➩  (2a)³ + (b)³ + (c)³ - 3(2a)(b)(c)

➩  8a³ + b³ + c³ - 6abc

Required Product :-

  • 8a³ + b³ + c³ - 6abc

Answered by Anonymous
2

Answer:

( 2a + b + c ) ( 4a² + b² + c² - 2ab - bc - 2ca )

➔  ( 2a + b + c ) ( 2a² + b² + c² - (2a)(b) - (b)(c) - (c)(2a)

➝  ( x + y + z ) ( x² + y² + z² - zy) :- x³ + y³ + z³ - 3xyz

➩  (2a)³ + (b)³ + (c)³ - 3(2a)(b)(c)

➩  8a³ + b³ + c³ - 6abc

➪ Required

Step-by-step explanation:

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