find the product 2m+3n(5m+4n)
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Answered by
1
Answer:
Let (a−b) and (c−d) be two binomials. By using the distributive law of multiplication over subtraction twice, we can find their product as given below.
(a−b)×(c−d)=a×(c−d)−b×(c−d)=(a×c−a×d)−(b×c−b×d)
=ac−ad−bc+bd
∴(3m−4n)(2m−3n)
=3m×(2m−3n)−4n×(2m−3n)
=[(3m×2m)−(3m×3n)]−[(4n×2m)−(4n×3n)]
=(6m2−9mn−8mn+12n2)
=(6m2−17mn+12n2)
Answered by
0
Answer:
2m(5m+4n)+3n(5m+4n)
10m²+8mn+15mn+12n²
10m²+23mn+12n²
using identity (a+b)²= a²+2ab+b²
(10m+12n)²
(10m+12n) (10m+12n)
- hope it will help you
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